2024-4-12 9:47 | 2024-4-12 9:54 | 0| 212 29 字| 几秒读完$$ a^b\equiv\begin{cases}\quad a^b&b<\varphi(m)\newline a^{b\operatorname{mod}\varphi(m)+\varphi(m)}&b\geq\varphi(m)&\end{cases}(\mathrm{mod~}m) $$